25x^2+12x-76=0

Solution for 25x^2+12x-76=0 equation:

25x^2+12x-76=0

a = 25; b = 12; c = -76;
Δ = b2-4ac
Δ = 122-4·25·(-76)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-88}{2*25}=\frac{-100}{50}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+88}{2*25}=\frac{76}{50}
=1+13/25
$